代码:
A:
#include #include #include using namespace std;int n, s;int main() { scanf("%d%d", &n, &s); int x, y; int flag = 1; int ans = 0; for (int i = 0; i
B:
#include #include const int N = 100005;typedef long long ll;int n;ll h[N];int main() { scanf("%d", &n); for (int i = 1; i h[i - 1]) { ll need = h[i] - h[i - 1]; if (now >= need) { now -= need; } else { ans += need - now; now = 0; } } else { now += h[i - 1] - h[i]; } } printf("%lld\n", ans); return 0;}
C:
#include #include const int N = 2005;typedef long long ll;int n;ll g[N][N], zhu[N + N], fu[N + N];int main() { scanf("%d", &n); for (int i = 0; i
D:
#include #include #include using namespace std;const int N = 1005;struct Num { int v[10], la;} num[N];bool cmp(Num a, Num b) { return a.la
E:
#include #include #include using namespace std;const int N = 100005;int n, q, val[N], f[N];vector g[N];void dfs(int u, int fa) { f[u] = fa; for (int i = 0; i 1) return u; u = f[u]; } return -1;}int main() { scanf("%d%d", &n, &q); for (int i = 1; i
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