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CodeforcesRound#277.5(Div.2)_html/css_WEB-ITnose

A. SwapSort

#include  #include  #include  #include using namespace std;int a[3010];int b[120];int vis[120];typedef pair  P;P m[3010];int main(){   #ifdef xxz    freopen("in.txt","r",stdin);    #endif // [xxz    int n;    cin>>n;    for(int i = 0; i  >a[i];    int sum = 0,ans = 0;    int i,j;    for(i = 0; i   a[j])           {                x = a[j];                y = j;           }        }        if(y != i)        {            m[sum].first = i;            m[sum++].second = y;            swap(a[i],a[y]);            ans++;        }    }    cout 

B. BerSU Ball

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! n boys and m girls are already busy rehearsing waltz, minuet, polonaise and quadrille moves.

We know that several boy&girl pairs are going to be invited to the ball. However, the partners' dancing skill in each pair must differ by at most one.

For each boy, we know his dancing skills. Similarly, for each girl we know her dancing skills. Write a code that can determine the largest possible number of pairs that can be formed from n boys and m girls.

Input

The first line contains an integer n (1?≤?n?≤?100) ? the number of boys. The second line contains sequence a1,?a2,?...,?an (1?≤?ai?≤?100), where ai is the i-th boy's dancing skill.

Similarly, the third line contains an integer m (1?≤?m?≤?100) ? the number of girls. The fourth line contains sequence b1,?b2,?...,?bm (1?≤?bj?≤?100), where bj is the j-th girl's dancing skill.

Output

Print a single number ? the required maximum possible number of pairs.

Sample test(s)

input

41 4 6 255 1 5 7 9 

output

input

41 2 3 4410 11 12 13 

output

input

51 1 1 1 131 2 3 

output


#include  #include  #include  #include using namespace std;int a[120];int b[120];int vis[120];int main(){   #ifdef xxz    freopen("in.txt","r",stdin);    #endif // [xxz    int n,m;    cin>>n;    for(int i = 0; i  >a[i];    sort(a,a+n);    cin>>m;    for(int i = 0; i  >b[i],vis[i] = 0;    sort(b,b+m);    int sum = 0;    int j;    for(int i =0; i  

C. Given Length and Sum of Digits...

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

You have a positive integer m and a non-negative integer s. Your task is to find the smallest and the largest of the numbers that have length m and sum of digits s. The required numbers should be non-negative integers written in the decimal base without leading zeroes.

Input

The single line of the input contains a pair of integers m, s (1?≤?m?≤?100,?0?≤?s?≤?900) ? the length and the sum of the digits of the required numbers.

Output

In the output print the pair of the required non-negative integer numbers ? first the minimum possible number, then ? the maximum possible number. If no numbers satisfying conditions required exist, print the pair of numbers "-1 -1" (without the quotes).

Sample test(s)

input

2 15 

output

69 96 

input

3 0 

output

-1 -1 

#include  #include #include  using namespace std;bool can(int m, int s){    if(s >= 0 && 9*m >= s) return true;    else return false;}int main(){    int m,s;    cin>>m>>s;    if(!can(m,s))    {        cout = 10)        {            cout  0 || (j == 0 && i > 1) ) && can(m - i, sum - j))                   {                       minn += char('0' + j);                       sum -= j;                       break;                   }            }            sum = s;               for(int i = 1; i  = 0; j--)            {                if(can(m - i, sum - j))                   {                       maxn += char('0' + j);                       sum -= j;                       break;                   }            }            cout 


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