#一、sql92标准 # 1 、等值连接 /* ① 多表等值连接的结果为多表的交集部分 ②n表连接,至少需要n-1个连接条件 ③ 多表的顺序没有要求 ④一般需要为表起别名 ⑤可以搭配前面介绍的所有子句使用,比如排序、分组、筛选 */ #案例1:查询女生和对应的男生 SELECT NAME,boyName FROM boys,beauty WHERE beauty.boyfriend_id = boys.id; #案例2:查询员工名和对应的部门名 SELECT last_name,department_name FROM employees,departments WHERE employees.`department_id` = departments.`department_id`; # 2 、为表起别名 /* ①提高语句的简洁度 ②区分多个重名的字段 注意:如果为表起了别名,则查询的字段就不能使用原来的表名去限定 */ #查询员工名、工种号、工种名 SELECT e.last_name,e.job_id,j.job_title FROM employees e,jobs j WHERE e.`job_id` = j.`job_id`; # 3 、 #查询员工名、工种号、工种名 SELECT e.last_name,e.job_id,j.job_title FROM jobs j,employees e WHERE e.`job_id` = j.`job_id`; # 4 、 #案例:查询有奖金的员工名、部门名 SELECT last_name,department_name,commission_pct FROM employees e,departments d WHERE e.`department_id` = d.`department_id` AND e.`commission_pct` IS NOT NULL; #案例2:查询城市名中第二个字符为o的部门名和城市名 SELECT department_name,city FROM departments d,locations l WHERE d.`location_id` = l.`location_id` AND city LIKE ‘ _o% ‘ ; # 5 、分组 #案例1:查询每个城市的部门个数 SELECT COUNT( * ) 个数,city FROM departments d,locations l WHERE d.`location_id` = l.`location_id` GROUP BY city; #案例2:查询有奖金的每个部门的部门名和部门的领导编号和该部门的最低工资 SELECT department_name,d.`manager_id`,MIN(salary) FROM departments d,employees e WHERE d.`department_id` = e.`department_id` AND commission_pct IS NOT NULL GROUP BY department_name,d.`manager_id`;
# 6 、排序 #案例:查询每个工种的工种名和员工的个数,并且按员工个数降序 SELECT job_title,COUNT( * ) FROM employees e,jobs j WHERE e.`job_id` = j.`job_id` GROUP BY job_title ORDER BY COUNT( * ) DESC;
# 7 、三表连接 #案例:查询员工名、部门名和所在的城市 SELECT last_name,department_name,city FROM employees e,departments d,locations l WHERE e.`department_id` = d.`department_id` AND d.`location_id` = l.`location_id` AND city LIKE ‘ s% ‘ ORDER BY department_name DESC; # 2 、非等值连接 #案例1:查询员工的工资和工资级别 SELECT salary,grade_level FROM employees e,job_grades g WHERE salary BETWEEN g.`lowest_sal` AND g.`highest_sal` AND g.`grade_level` = ‘ A ‘ ; # 3 、自连接 #案例:查询 员工名和上级的名称 SELECT e.employee_id,e.last_name,m.employee_id,m.last_name FROM employees e,employees m WHERE e.`manager_id` =m.`employee_id`;
#一、查询编号> 3的女生的男朋友信息,如果有则列出详细,如果没有,用null填充 SELECT b.id,b.name,bo. * FROM beauty b LEFT OUTER JOIN boys bo ON b.`boyfriend_id` = bo.`id` WHERE b.`id` > 3 ; #二、查询哪个城市没有部门 SELECT city FROM departments d RIGHT OUTER JOIN locations l ON d.`location_id` = l.`location_id` WHERE d.`department_id` IS NULL; #三、查询部门名为SAL或IT的员工信息 SELECT e. * ,d.department_name,d.`department_id` FROM departments d LEFT JOIN employees e ON d.`department_id` = e.`department_id` WHERE d.`department_name` IN( ‘ SAL ‘ , ‘ IT ‘ );
#二、sql99语法
/*
语法:
select 查询列表
from 表1 别名 【连接类型】
join 表2 别名
on 连接条件
【where 筛选条件】
【group by 分组】
【having 筛选条件】
【order by 排序列表】
分类:
内连接(★):inner
外连接
左外(★):left 【outer】
右外(★):right 【outer】
全外:full【outer】
交叉连接:cross
*/
#一)内连接
/*
语法:
select 查询列表
from 表1 别名
inner join 表2 别名
on 连接条件;
分类:
等值
非等值
自连接
特点:
①添加排序、分组、筛选
②inner可以省略
③ 筛选条件放在where后面,连接条件放在on后面,提高分离性,便于阅读
④inner join连接和sql92语法中的等值连接效果是一样的,都是查询多表的交集
*/
# 1 、等值连接
#案例1.查询员工名、部门名
SELECT last_name,department_name
FROM departments d
JOIN employees e
ON e.`department_id` = d.`department_id`;
#案例2.查询名字中包含e的员工名和工种名(添加筛选)
SELECT last_name,job_title
FROM employees e
INNER JOIN jobs j
ON e.`job_id` = j.`job_id`
WHERE e.`last_name` LIKE ‘ %e% ‘ ;
# 3 . 查询部门个数>3的城市名和部门个数,(添加分组+ 筛选)
#①查询每个城市的部门个数
#②在①结果上筛选满足条件的
SELECT city,COUNT( * ) 部门个数
FROM departments d
INNER JOIN locations l
ON d.`location_id` = l.`location_id`
GROUP BY city
HAVING COUNT( *)> 3 ;
#案例4.查询哪个部门的员工个数 > 3的部门名和员工个数,并按个数降序(添加排序)
#①查询每个部门的员工个数
SELECT COUNT( * ),department_name
FROM employees e
INNER JOIN departments d
ON e.`department_id` = d.`department_id`
GROUP BY department_name
#② 在①结果上筛选员工个数 > 3的记录,并排序
SELECT COUNT( * ) 个数,department_name
FROM employees e
INNER JOIN departments d
ON e.`department_id` = d.`department_id`
GROUP BY department_name
HAVING COUNT( *)> 3
ORDER BY COUNT( * ) DESC;
# 5 .查询员工名、部门名、工种名,并按部门名降序(添加三表连接)
SELECT last_name,department_name,job_title
FROM employees e
INNER JOIN departments d ON e.`department_id` = d.`department_id`
INNER JOIN jobs j ON e.`job_id` = j.`job_id`
ORDER BY department_name DESC;
#二)非等值连接
#查询员工的工资级别
SELECT salary,grade_level
FROM employees e
JOIN job_grades g
ON e.`salary` BETWEEN g.`lowest_sal` AND g.`highest_sal`;
#查询工资级别的个数 > 20的个数,并且按工资级别降序
SELECT COUNT( * ),grade_level
FROM employees e
JOIN job_grades g
ON e.`salary` BETWEEN g.`lowest_sal` AND g.`highest_sal`
GROUP BY grade_level
HAVING COUNT( *)> 20
ORDER BY grade_level DESC;
#三)自连接
#查询员工的名字、上级的名字
SELECT e.last_name,m.last_name
FROM employees e
JOIN employees m
ON e.`manager_id` = m.`employee_id`;
#查询姓名中包含字符k的员工的名字、上级的名字
SELECT e.last_name,m.last_name
FROM employees e
JOIN employees m
ON e.`manager_id` = m.`employee_id`
WHERE e.`last_name` LIKE ‘ %k% ‘ ;
#二、外连接
/*
应用场景:用于查询一个表中有,另一个表没有的记录
特点:
1、外连接的查询结果为主表中的所有记录
如果从表中有和它匹配的,则显示匹配的值
如果从表中没有和它匹配的,则显示null
外连接查询结果=内连接结果+主表中有而从表没有的记录
2、左外连接,left join左边的是主表
右外连接,right join右边的是主表
3、左外和右外交换两个表的顺序,可以实现同样的效果
4、全外连接=内连接的结果+表1中有但表2没有的+表2中有但表1没有的
*/
#引入:查询男朋友 不在男神表的的女神名
SELECT * FROM beauty;
SELECT * FROM boys;
#左外连接
SELECT b. *,bo.*
FROM boys bo
LEFT OUTER JOIN beauty b
ON b.`boyfriend_id` = bo.`id`
WHERE b.`id` IS NULL;
#案例1:查询哪个部门没有员工
#左外
SELECT d. * ,e.employee_id
FROM departments d
LEFT OUTER JOIN employees e
ON d.`department_id` = e.`department_id`
WHERE e.`employee_id` IS NULL;
#右外
SELECT d. * ,e.employee_id
FROM employees e
RIGHT OUTER JOIN departments d
ON d.`department_id` = e.`department_id`
WHERE e.`employee_id` IS NULL;
#全外
USE girls;
SELECT b. *,bo.*
FROM beauty b
FULL OUTER JOIN boys bo
ON b.`boyfriend_id` = bo.id;
#交叉连接
SELECT b. *,bo.*
FROM beauty b
CROSS JOIN boys bo;
#sql92和 sql99pk
/*
功能:sql99支持的较多
可读性:sql99实现连接条件和筛选条件的分离,可读性较高
*/
mysql连接查询
标签:实现 内连接 顺序 mis class city 就会 语句 mission
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