数据库学习

1. 基本的经典查询

 #基本的查询语句
SELECT *
FROM data.`dataanalyst` 
WHERE city =‘上海‘
AND (education = ‘本科‘
OR workYear = ‘1-3年‘
)
AND secondType LIKE ‘%开发%‘  #字段包含开发
OR secondType LIKE ‘后端%‘  #优先级:()> AND > OR
 

结果：

2. 不同城市招聘公司的数量，需要用distinct去重

 #不同城市招聘公司的数量，需要用distinct去重
SELECT 
city,
COUNT(positionId),
COUNT(DISTINCT(companyId)) 
FROM data.`dataanalyst`
GROUP BY city
 

3. 不同城市，学历的招聘岗位数目

 #不同城市，学历的数目
SELECT city,education,COUNT(1) FROM data.`dataanalyst`
GROUP BY city,education
 

4. 不同城市电子商务岗位的数量

 #不同城市电子商务岗位的数量
SELECT city,COUNT(1) FROM data.`dataanalyst`
WHERE industryField LIKE ‘%电子商务%‘
GROUP BY city
HAVING COUNT(1)>50 #二次过滤，挑选拥有电子商务岗位数量为50以上的城市
 

5. 这是第4题的改写

上面也可以写成这样

把where合并入having中

 #不同城市电子商务岗位的数量
SELECT city,COUNT(1) FROM data.`dataanalyst`
GROUP BY city
HAVING COUNT(IF(industryField LIKE ‘%电子商务%‘,1,NULL))>50 
 

得出的结果完全相同

6. 不同城市下，电子商务岗位在所有岗位中的占比

注意：AS的别名在where中起名之后，只能在having，order by中使用

 select
city,
COUNT(IF(industryField LIKE ‘%电子商务%‘,1,NULL)) as emarket,
count(1) as total,
COUNT(IF(industryField LIKE ‘%电子商务%‘,1,NULL))/count(1) as proportion
from data.`dataanalyst`
group by city
having  emarket>10
order by proportion
 

7. 截取薪资上限和下限

 SELECT 
LEFT(salary,LOCATE(‘k‘,salary)-1) AS ‘minSalary‘,
RIGHT(salary,LOCATE(‘-‘,salary)-1) AS ‘最大薪资数据‘,
#去掉最后的k
LEFT(RIGHT(salary,LOCATE(‘-‘,salary)-1),LOCATE(‘k‘,RIGHT(salary,LOCATE(‘-‘,salary)-1))-1) AS ‘maxSalary‘,
salary
FROM data.`dataanalyst`
 

8. 是第7题薪资上下限的改写，使用substr函数

 SELECT
LEFT(salary,LOCATE(‘k‘,salary)-1) AS ‘minSalary‘,
LOCATE(‘-‘,salary),
LENGTH(salary),
#substr(字符串，从哪里开始，截取长度)
SUBSTR(salary,LOCATE(‘-‘,salary)+1,LENGTH(salary)-LOCATE(‘-‘,salary)-1) AS ‘maxSalary‘,
salary
FROM data.`dataanalyst`
 

9. 子查询实现对平均薪资分区

 SELECT 
    CASE
        WHEN (minSalary+maxSalary)/2 <=10 THEN ‘0-10k‘
        WHEN (minSalary+maxSalary)/2 <=20 THEN ‘10k-20k‘
        WHEN (minSalary+maxSalary)/2 <=30 THEN ‘20k-30k‘
        ELSE ‘30k以上‘
    END AS ‘平均薪资范围‘,
	(minSalary+maxSalary)/2 AS ‘aveSalary‘,
	salary
FROM(
    SELECT
    LEFT(salary,LOCATE(‘k‘,salary)-1) AS ‘minSalary‘,
    LOCATE(‘-‘,salary),
    LENGTH(salary),
    #substr(字符串，从哪里开始，截取长度)
    SUBSTR(salary,LOCATE(‘-‘,salary)+1,LENGTH(salary)-LOCATE(‘-‘,salary)-1) AS ‘maxSalary‘,
    salary
    FROM data.`dataanalyst`) AS t
 

注意对表子查询的话，最后要加上 as t

数据库学习

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