这样的sql语句存在sql语法错误,但是再加一层就行。如:
SELECT uid, open_acc_status, open_acc_time, mobile_num, email, reg_type FROM UserInfo WHERE uid IN ( SELECT i.uid FROM ( SELECT * FROM InviteCode WHERE invite_uid = 100000004 LIMIT 1 OFFSET 1 ) as i)
在最后的的from table改成 Select * .
Error querying database. Cause: com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: This version of MySQL doesn't yet support 'LIMIT & IN/ALL/ANY/SOME subquery' 错误解决方案
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