RestTemplate 401错误
调用第三方api 若是服务返回状态码不为200，默认会执行DefaultResponseErrorHandler
异常处理
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@Override public void handleError(ClientHttpResponse response) throws IOException { HttpStatus statusCode = getHttpStatusCode(response); switch (statusCode.series()) { case CLIENT_ERROR: throw new HttpClientErrorException(statusCode, response.getStatusText(), response.getHeaders(), getResponseBody(response), getCharset(response)); case SERVER_ERROR: throw new HttpServerErrorException(statusCode, response.getStatusText(), response.getHeaders(), getResponseBody(response), getCharset(response)); default : throw new RestClientException( "Unknown status code [" + statusCode + "]" ); } } |
判断是否异常
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protected boolean hasError(HttpStatus statusCode) { return (statusCode.series() == HttpStatus.Series.CLIENT_ERROR || statusCode.series() == HttpStatus.Series.SERVER_ERROR); } |
通常会直接已异常形势抛出，若不特殊处理无法获取返回提示信息。
需要捕捉HttpClientErrorException 异常，则可获取返回信息
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try { ...... } catch (HttpClientErrorException e) { String resBody = e.getResponseBodyAsString(); log.info( "客户端异常返回:{}" , resBody); return new ResponseEntity<>(JSON.parseObject(resBody, res), e.getStatusCode()); } |
一开始我这样写，死活返回的都是null
原来跟我设置的requestFactory有关
采用SimpleClientHttpRequestFactory 无法获取提示
需要换成 HttpComponentsClientHttpRequestFactory
RestTemplate通过对象传参，response的body为空讨论
代码复现
实体类
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@Entity @Table (name = "a" ,schema = "a" ) @JsonIgnoreProperties (value = { "a" }) @Setter @Generated public class C { @Id @GeneratedValue private Integer id; @Column (name = "diseaseName" ,length = 255 ,nullable = false ,unique = true ) private String diseaseName; @Column (name = "description" ,length = 255 ,nullable = false ,unique = true ) private String description; @Column (name = "department" ,length = 255 ,nullable = false ,unique = true ) private String department; } controller @ResponseBody @RequestMapping (value = "" ,method = RequestMethod.POST) public Response APIcreate( @RequestBody C c) { String json = JSONUtil.toJSONString(c); HttpHeaders headers = new HttpHeaders(); headers.setContentType(MediaType.APPLICATION_JSON_UTF8); HttpEntity<String> entity = new HttpEntity<>(json, headers); String url = "http://localhost:3001/c" ; ResponseEntity<Commondisease> responseEntity = restTemplate.postForEntity(url, entity, C. class ); return new ResponseData(ExceptionMsg.SUCCESS, responseEntity); } |
返回结果截图：
返回结果为空的讨论：返回的C类是jpa封装后的类，即使通过json工具，也无法转换成功
解决办法一：实体类转成普通类
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import lombok.AllArgsConstructor; import lombok.Data; import lombok.NoArgsConstructor; @Data @AllArgsConstructor @NoArgsConstructor public class C { private Integer id; private String diseaseName; private String description; private String department; } @ResponseBody @RequestMapping (value = "" ,method = RequestMethod.POST) public Response APIcreate( @RequestBody C c) { //C c = new Commondisease(1,"zhangsan","11","2222"); String json = JSONUtil.toJSONString(c); HttpHeaders headers = new HttpHeaders(); headers.setContentType(MediaType.APPLICATION_JSON_UTF8); HttpEntity<String> entity = new HttpEntity<>(json, headers); String url = "http://localhost:3001/c/" ; ResponseEntity<Commondisease> responseEntity = restTemplate.postForEntity(url,entity,C. class ); return new ResponseData(ExceptionMsg.SUCCESS,responseEntity); } |
返回成功
解决办法二：添加注解
@Data
以上为个人经验，希望能给大家一个参考，也希望大家多多支持。
原文链接：https://blog.csdn.net/xuyw10000/article/details/88790391
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