Spring的@Scheduled 如何动态更新cron表达式

@Scheduled (cron = "0/5 * * * * ?" )

    private void test() {

        log.info( "业务处理逻辑。。。5秒一次" );

    }

@Lazy ( false )

@Component

@EnableScheduling

public class SpringDynamicCornTask implements SchedulingConfigurer {

     private static final Logger logger = LoggerFactory.getLogger(SpringDynamicCornTask. class );

     private static final String DEFAULT_CRON = "0/5 * * * * ?" ;

     private String cron = DEFAULT_CRON;

     @Override

     public void configureTasks(ScheduledTaskRegistrar taskRegistrar) {

         taskRegistrar.addTriggerTask(() -> {

             logger.info( "真正的任务执行逻辑。。。" );

         }, triggerContext -> {

             CronTrigger trigger = new CronTrigger(cron);

             return trigger.nextExecutionTime(triggerContext);

         });

     }

     public void setCron(String cron) {

         System.out.println( "原来的cron：" + this .cron+ "更新后的cron：" +cron);

         this .cron = cron;

     }

     public String getCron() {

         return this .cron;

     }

}

@RestController

public class TestController {

     @Autowired

     private SpringDynamicCornTask springDynamicCornTask;

     @RequestMapping ( "/setCron" )

     public String setCron(){

         springDynamicCornTask.setCron( "0/10 * * * * ?" );

         return "success" ;

     }

     @RequestMapping ( "/getCron" )

     public String getCron(){

         String cron = springDynamicCornTask.getCron();

         return "cron:" +cron;

     }

}