下载地址：SqlFunction_udf_Week.rar
以下内容于20120105更新：
2012年刚到，开发的 软件 使用这个函数发现bug。2012年第一周应该是2012-01-01至2012-01-07，但此函数却把2012-01-08至2012-01-14当作第一周。
就此bug对此函数修改如下：
复制代码 代码如下:
SET ANSI_NUL HdhCmsTestcppcns测试数据 LS ON
GO
SET QUOTED_IDENTIFIER ON
GO
ALTER FUNCTION [dbo].[udf_Week]
(
@StartYear INT,
@EndYear INT
)
RETURNS @Week TABLE([WeekId] INT IDENTITY(1,1) PRIMARY KEY,[Year] [INT] NULL,[Week] [INT] NULL,[StartDate] [DATETIME] NULL,[EndDate] [DATETIME] NULL)
AS
BEGIN
DECLARE @YearStartDate DATETIME
DECLARE @YearEndDate DATETIME
DECLARE @WeekStartDate DATETIME
DECLARE @WeekEndDate DATETIME
DECLARE @Weeks INT
WHILE @StartYear <= @EndYear
BEGIN
SET @YearStartDate = CAST((CAST(@StartYear AS VARCHAR(4)) + '-01-01') AS DATETIME)
SET @YearEndDate= CAST((CAST(@StartYear AS VARCHAR(4))+ '-12-31') AS DATETIME)
SET @Weeks = 1
IF DATEPART( dw ,@YearStartDate android ) > 4
SET @YearStartDate = DATEADD(DAY,(8 - DATEPART(DW,@YearStartDate)) ,@YearStartDate)
ELSE
SET @YearStartDate = DATEADD(DAY,(-(DATEPART(DW,@YearStartDate)-1)),@YearStartDate)
S android ET @WeekStartDate = @YearStartDate
SET @WeekEndDate = DATEADD(DAY,6,@WeekStartDate)
WHILE DATEDIFF(DAY,@WeekStartDate,@YearEndDate) >= 4
BEGIN
INSERT INTO @Week([Year],[Week],[StartDate],[EndDate]) VALUES (@Start python Year,@Weeks,@WeekStartDate,@WeekEndDate)
SET @Weeks = @Weeks + 1
SET @WeekStartDate = @WeekStartDate + 7
SET @WeekEndDate = @WeekEndDate + 7
END
SET @StartYear = @Sta 编程客栈 rtYear + 1
END
RETURN
END
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