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php ajaxfileupload实现ajax文件上传功能 - php上传下载

php ajaxfileupload实现ajax文件上传功能

最近公司要做一个上传头像的功能,我们希望用户点击上传就实现了文件上传并不需要跳转页面了,下面我们就一起来看个例子吧.

可以批量进行添加上传,简单方便,代码如下:

<script type= "text/javascript"  src= "jquery-1.5.1.min.js" ></script>        <script     type= "text/javascript"  src= "ajaxfileupload.js" ></script>      <form id= "upform"  action= ""  method= "post"  enctype= "multipart/form-data" >      <input id= 'fname'  size= '80'  /><br> <input type= "file"  name= "file1"          id= "file1"  size= "30"  /> <input type= "button"  value= "上传"          onclick= "return ajaxFileUpload();"  /> <span id= "msg"          style= "display: none" >UpLoading...</span>  </form>     <script type= "text/javascript" >  var  str =  '' ;    function  ajaxFileUpload(){        $( "#msg" )        .ajaxStart( function (){           $( this ).show();        });         /*         .ajaxComplete(function(){            $(this).hide();         });         */         $.ajaxFileUpload(        {           url: 'up_deal.php' ,           secureuri: false ,           fileElementId: 'file1' ,           dataType:  'text' ,            //data:{name:'qinmi', id:'123'},            success:  function (data){                   if (data== 'error' ){                     $( '#msg' ).html( "<span style='color:red'>上传失败</span>" );                  } else {                       $( '#msg' ).html( "<span style='color:green'>上传成功</span>" );                      str +=  data+ '@' ;                      $( '#fname' ).val(str);                  }               }           }        );         return   false ;    }    </script> 

up_deal.php代码如下:

<?php    if  ((( $_FILES [ "file1" ][ "type" ] ==  "image/gif" )    || ( $_FILES [ "file1" ][ "type" ] ==  "image/jpeg" )    || ( $_FILES [ "file1" ][ "type" ] ==  "image/bmp" )    || ( $_FILES [ "file1" ][ "type" ] ==  "image/pjpeg" ))    && ( $_FILES [ "file1" ][ "size" ] < 100000)){ //100KB          $extend  =  explode ( "." , $_FILES [ "file1" ][ "name" ]);         $key  =  count ( $extend )-1;         $ext  =  "." . $extend [ $key ];         $newfile  = time(). $ext ;             if (! file_exists ( 'upload' )){ mkdir ( 'upload' );}        move_uploaded_file( $_FILES [ "file1" ][ "tmp_name" ], "upload/"  .  $newfile );        @unlink( $_FILES [ 'file1' ]);         echo   $newfile ;    } else  {         echo   'error' ;    }    ?> 

其中需要用到ajaxfileupload.js 这个文件.

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