总结有关python八大排序算法（下）

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def quick_sort(list):
  little = []
  pivotList = []
  large = []
  # 递归出口
  if len(list) <= 1:
    return list
  else:
    # 将第一个值做为基准
    pivot = list[0]
    for i in list:
      # 将比基准小的值放到less数列
      if i < pivot:
        little.append(i)
      # 将比基准大的值放到more数列
      elif i > pivot:
        large.append(i)
      # 将和基准相同的值保存在基准数列
      else:
        pivotList.append(i)
    # 对less数列和more数列继续进行快速排序
    little = quick_sort(little)
    large = quick_sort(large)
    return little + pivotList + large 

#!/usr/bin/env python
#coding:utf-8
'''
file:python-8sort.py
date:9/1/17 9:03 AM
author:lockey
email:lockey@123测试数据
desc:python实现八大排序算法
'''
lst = [65,568,9,23,4,34,65,8,6,9]
def quick_sort(list):
  if len(list) <= 1:
    return list
  else:
    pivot = list[0]
    return quick_sort([x for x in list[1:] if x < pivot]) +         [pivot] +         quick_sort([x for x in list[1:] if x >= pivot]) 

# -*- coding: UTF-8 -*-
'''
Created on 2017年9月2日
Running environment：win7.x86_64 eclipse python3
@author: Lockey
'''
lst = [65,568,9,23,4,34,65,8,6,9]
def adjust_heap(lists, i, size):# 调整堆
  lchild = 2 * i + 1;rchild = 2 * i + 2
  max = i
  if i < size / 2:
    if lchild < size and lists[lchild] > lists[max]:
      max = lchild
    if rchild < size and lists[rchild] > lists[max]:
      max = rchild
    if max != i:
      lists[max], lists[i] = lists[i], lists[max]
      adjust_heap(lists, max, size)
def build_heap(lists, size):# 创建堆
  halfsize = int(size/2)
  for i in range(0, halfsize)[::-1]:
    adjust_heap(lists, i, size)
def heap_sort(lists):# 堆排序
  size = len(lists)
  build_heap(lists, size)
  for i in range(0, size)[::-1]:
    lists[0], lists[i] = lists[i], lists[0]
    adjust_heap(lists, 0, i)
    print(lists) 

# -*- coding: UTF-8 -*-
'''
Created on 2017年9月2日
Running environment：win7.x86_64 eclipse python3
@author: Lockey
'''
lst = [65,568,9,23,4,34,65,8,6,9]
def merge(left, right):
  i, j = 0, 0
  result = []
  while i < len(left) and j < len(right):
    if left[i] <= right[j]:
      result.append(left[i])
      i += 1
    else:
      result.append(right[j])
      j += 1
  result += left[i:]
  result += right[j:]
  print(result)
  return result
def merge_sort(lists):# 归并排序
  if len(lists) <= 1:
    return lists
  num = int(len(lists) / 2)
  left = merge_sort(lists[:num])
  right = merge_sort(lists[num:])
  return merge(left, right) 

# -*- coding: UTF-8 -*-
'''
Created on 2017年9月2日
Running environment：win7.x86_64 eclipse python3
@author: Lockey
'''
import math
lst = [65,56,9,23,84,34,8,6,9,54,11]
#因为列表数据范围在100以内，所以将使用十个桶来进行排序
def radix_sort(lists, radix=10):
  k = int(math.ceil(math.log(max(lists), radix)))
  bucket = [[] for i in range(radix)]
  for i in range(1, k+1):
    for j in lists:
      gg = int(j/(radix**(i-1))) % (radix**i)
      bucket[gg].append(j)
    del lists[:]
    for z in bucket:
      lists += z
      del z[:]
      print(lists)
  return lists 

程序运行测试结果：

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