func a() int {
defer b()
return 0
} f, _ := os.Open(filename) defer f.Close()
func CopyFile(dstName, srcName string) (written int64, err error) {
src, err := os.Open(srcName)
if err != nil {
return
}
dst, err := os.Create(dstName)
if err != nil { //1
return
}
written, err = io.Copy(dst, src)
dst.Close()
src.Close()
return
} func CopyFile(dstName, srcName string) (written int64, err error) {
src, err := os.Open(srcName)
if err != nil {
return
}
defer src.Close()
dst, err := os.Create(dstName)
if err != nil {
return
}
defer dst.Close()
return io.Copy(dst, src)
} package main
import (
"fmt"
)
func main() {
defer func() {
if ok := recover(); ok != nil {
fmt.Println("recover")
}
}()
panic("error")
} defer func() { fmt.Println("1") }()
defer func() { fmt.Println("2") }()
defer func() { fmt.Println("3") }() func a() {
i := 0
defer fmt.Println(i)
i++
return
} func calc(index string, a, b int) int {
ret := a + b
fmt.Println(index, a, b, ret)
return ret
}
func main() {
a := 1
b := 2
defer calc("1", a, calc("10", a, b))
a = 0
return
} 10 1 2 3 1 1 3 4
func c() (i int) {
defer func() { i++ }()
return 1
} 被 defer 的函数是在 return 之后执行,可以修改带名称的返回值,上面的函数 c 返回的是 2。
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