使用二分法（BisectionMethod）求平方根。

使用二分法（Bisection Method）求平方根。

def sqrtBI(x, epsilon):
    assert x>0, 'X must be non-nagtive, not ' + str(x)
    assert epsilon > 0, 'epsilon must be postive, not ' + str(epsilon)
  
    low = 0
    high = x
    guess = (low + high)/2.0
    counter = 1
    while (abs(guess ** 2 - x) > epsilon) and (counter  

那如何求0.25的平方根呢？

只要略微改动上面的代码即可。注意6行和7行的代码。

def sqrtBI(x, epsilon):
    assert x>0, 'X must be non-nagtive, not ' + str(x)
    assert epsilon > 0, 'epsilon must be postive, not ' + str(epsilon)
  
    low = 0
    high = max(x, 1.0)
    ## high = x
    guess = (low + high)/2.0
    counter = 1
    while (abs(guess ** 2 - x) > epsilon) and (counter  

验证一下：

>>> sqrtBI(0.25,0.000001)

>>> 0.5

查看更多关于使用二分法（BisectionMethod）求平方根。的详细内容...