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【叶子函数分享四十】将一个正整数分解为m个2的n次方的和

-- ============================================= -- Author: maco_wang -- Create date: 2011-01-21 -- Description: 将一个正整数分解为 m 个 2 的 n 次方的和 -- ============================================= go -- 创建函数 CREATE function GetSum

-- =============================================

-- Author:

-- Create date:

-- Description: 将一个正整数分解为 m 个 2 的 n 次方的和 >

-- =============================================

go

-- 创建函数

CREATE function GetSumSequence ( @num INT )

returns nvarchar ( 200 )

AS

BEGIN

DECLARE @numc INT

SET @numc = @num

DECLARE @numstr VARCHAR ( 50 )

SET @numstr = ''

WHILE ( @num 0 )

BEGIN

SET @numstr = @numstr + CONVERT ( CHAR ( 1 ), @num % 2 )

SET @num = @num / 2

END

--SELECT REVERSE(@numstr)

DECLARE @i INT

SET @i = LEN ( @numstr )

DECLARE @j VARCHAR ( MAX )

SET @j = ''

WHILE ( @i > 0 )

BEGIN

IF ( SUBSTRING ( REVERSE ( @numstr ), LEN ( @numstr ) - @i + 1 , 1 ) = '1' )

SELECT @j = @j + '+2^' + CAST ( @i - 1 AS VARCHAR ( 10 ))

SET @i = @i - 1

END

return ( CAST ( @numc AS VARCHAR ( 100 )) + '=' + STUFF ( @j , 1 , 1 , '' ))

END

go

-- 测试示例

select dbo . GetSumSequence ( 12 )

select dbo . GetSumSequence ( 65 )

select dbo . GetSumSequence ( 892 )

select dbo . GetSumSequence ( 1919191 )

-- 运行结果

/*

12=2^3+2^2

65=2^6+2^0

892=2^9+2^8+2^6+2^5+2^4+2^3+2^2

1919191=2^20+2^19+2^18+2^16+2^14+2^11+2^7+2^6+2^4+2^2+2^1+2^0

*/

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