java获取键盘输入的数字,并进行排序的方法

class date19_02

  {

   public static void main(string[] arg){

    sortone();

   }

  public static void sortone(){

    scanner sc1 = new scanner(system.in); 

    system.out.print( "\n请输入第1个整数:" );

    int num1 = sc1.nextint();

    system.out.print( "输入的第1个数字：\t" +num1+ "\n" );

    system.out.print( "\n请输入第2个整数:" );

    scanner sc2 = new scanner(system.in);

    int num2 = sc2.nextint();

    if (num2 != num1){

     system.out.print( "输入的第2个数字：\t" +num2+ "\n" );

    } else {

     system.out.print( "输入的第2个数与第1个重复,请重试\n" );

     return ;}

    system.out.print( "\n请输入第3个整数(输满3个即止):" );

    scanner sc3 = new scanner(system.in);

    int num3 = sc3.nextint();

    if (num3 != num2){

     system.out.print( "输入的第3个数字：\t" +num3+ "\n" );}

    else {

     system.out.print( "输入的第3个数有重复,请重试\n" );

     return ;}

    int smaller= 0 , bigger= 0 , max= 0 ; //类变量须在声明时初始化

   if (num1 < num2){smaller = num1; bigger = num2;}

    else if (num1 > num2){bigger = num1; smaller = num2;}

    if (num3 > bigger){max = num3;}

    else {max = bigger;}

    system.out.print( "\n升序排列数字：\n\t" );

    system.out.print(smaller+ " " +bigger+ " " +max);

   }

  }

import java.util.arrays; //此源文件的所有导入须写在第一个类之前！

class date19_02

  {

  public static void main(string[] arg){

    sorttwo();

   }

  public static void sorttwo(){

    int [] array1 = new int [ 3 ];

    for ( int x= 0 ; x<array1.length; x++){

    scanner sc = new scanner(system.in);

    system.out.print( "\n请输入整数(输满3个即止):" );

    int num1 = sc.nextint();

    system.out.print( "输入的第" +(x+ 1 )+ "个数字：" +num1);

    array1[x] = num1;

    }

   arrays.sort(array1); //使用java标准库的排序功能模块

  system.out.print( "\n\t小==>大排列：\n" );

   for ( int y= 0 ; y<array1.length; y++){

    system.out.print(array1[y]+ " " ); //升序排列后,输出

   }

   }

  }